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What a stupid comment!
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What a stupid, idiotic comment! This is in relation to a cheap, stand alone alarm with an infra red remote that I used briefly in my workshop/shed when I first built it and before getting round to installing something permanent. Someone had made a youtube video about it and I commented it about the issue I had with my lights disarming it via the infra red remote sensor. Fluorescent lighting may not be the very latest tech, but its still perfectly valid and does the job well. I hate this mindset that everybody has to be using the most bang up to date technology and that if it isn't it's ready for landfill. There's so much unnecessary waste due to this kind of attitude.
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On unrelated note, the detector control protocol gotta be quite poorly thought out if the interference from a single frequency of an HF ballast (that works at close frequency to that of IR remotes, but does not carry any modulated signals) not just jams the remote (this is quite common) but actually gets it to do actions. I wonder what it would do if fired at with a few different TV or other appliance remotes.... If this happened with a magnetic ballast then im at a loss completely in regards to the design of this detector
Lol 10kw at 12 volts... that's like 800 amps.
Saying that though, I have seen car stereo installs that have drawn so much power that the windings in the alternator have burned black!
RMS is the root mean square of multiple samples of the value (of the current, voltage, power etc) taken over some time over which we do the "averaging" (assuming the samples are taken in a "fair" way to represent all what's going on). For sine voltage or current, the RMS of what goes over one cycle happens to be 1/sqrt2 (1/1.414) of the peak value
For AC circuit with sine wave, the RMS voltaege is 1/sqrt2 of the peak, the RMS current is 1/sqrt2 of the peak, and for both the signal is AC so the PTP (peak to peak) is double the peak. The RMS power is then 1/2 of the peak power (VxI = 1/sqrt2 x 1/sqrt2), and as power is positive throughout the entire AC cycle, the PTP value is same as the peak and not double
For anything else you must evaluate what is really going on, there are no generalized rules...
If you are delivering a sine audio signal through an amplifier powered with DC, then the voltage stays constant (disregarding voltage drop), and current draw at the amp input is the rectified output (disregarding losses and storage in capacitors etc). So the peak would be the peak current, the RMS would be the 1/sqrt2 of the peak, and since the current never goes backwards (the amp does not regenerate back into the battery) the negative peak of the current is 0A. In this case the PTP is simply same as the peak. As the voltage is constant, the power behaves the same as the current
If there is some smoothing of the power draw at the amplifier DC input (say by a huge value capacitor), the positive peak current will be lowered to some extent as part of it will be delivered from the capacitor (and not from the DC input), and the negative peak will be above zero (i.e. still positive) as when the amp itself does not draw current, the cap is drawing current for recharging. In this case the Average current will stay the same, but peak will be lower, PTP lower, and RMS also somewhat lower (this is because of the square in the equation, which makes the effect of the peak more pronounced in the overall result. RMS is not the same as Average)
Also, audio signals can have peaks which far exceed the RMS x sqrt2 value. Although (depending on the specific sound) they may be far inbetween, so not affect the DC supply in an "overloading to overheating" sense, but if it is unable to deliver the required power, there will be a momentary voltage drop, that will lead to distortion in the sound and maybe affect other devices powered from the same supply