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File information | |
Filename: | ballasts.jpg |
Album name: | lasagafield / Lasagafield's Lights |
Manufacturer: | DKY |
Wattage: | 14w |
Filesize: | 1284 KiB |
Date added: | 01 Sep, 2018 |
Dimensions: | 2208 x 1593 pixels |
Displayed: | 44 times |
URL: | http://80.229.24.59:9232/gallery/displayimage.php?pid=8696 |
Favourites: | Add to Favourites |
F14T12 lamps.
The use of 14..20W ballast for 14..20W lamps is affected by voltage. At first approximation (disregarding ballast coil resistance, lamp power factor, etc), ballast and lamp behave as :
V(lamp arc)^2 + V(ballast drop out)^2 = V(line voltage)
I = V(ballast drop out) / X
Where X is the ballast impedance, which is defined by its structure (number of turns, core dimensions, etc). If we disregard effects like saturation, then X is constant for each ballast
When we put different lamps with the ballast, we change V(lamp arc), it is generally lower the shorter the lamp is. Therefore, V(ballast drop out) changes accordingly
But by how much ?
Compared to 120V, the change of few 10's volts in lamp arc voltage is more significant. Lower voltage lamp put on "20W T12" ballast will increase the voltage dropped on the ballast, and therefore its current, so the ballast will supply higher current to a lower voltage lamp
Compared to 230V, the change in lamp arc voltage is less significant, (due to the voltage drops being out of phase, the change in ballast drop out voltage is even further less significant). So the ballast will put out current closer to that with the first lamp. I.e. the increase in current will be less
This change in current does happen on 230V with lamps with higher arc voltages (which are more on the same scale as the supplied 230V), thats how 20W T12 ballast can supply 370mA with 20W lamp and as low as 320mA with a high voltage PL of 24..26W
And yes now I look at the picture closer I see the 0.47 is actually the power factor, doh!